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Forward from: LAKSHYA BATCH PHYSICS WALLAH
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PW बच्चों की सुनता है 🫡 || 1.5 Lakh Courses हुए Rs. 3500 ke 🔥

PW Skills is announcing the launch of the following programs, Saare courses dono hindi or english languages me available h or inke links aapko provide kiye jaa rhe h

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Forward from: LAKSHYA BATCH PHYSICS WALLAH
Wishing Everyone a Very Happy, Healthy and Prosperous New Year!! 🎉

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Forward from: LAKSHYA BATCH PHYSICS WALLAH
CBSE Date Sheet- 23 ( 10th and 12th).pdf
3.0Mb
CBSE Official Datesheet for 10th and 12th Class 🤓🤩

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Forward from: LAKSHYA BATCH PHYSICS WALLAH
NEET UG 2022 Results are out!
Check now-


https://testservices.nic.in/resultservices/neet-2022-auth




Forward from: LAKSHYA BATCH PHYSICS WALLAH
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Forward from: LAKSHYA BATCH PHYSICS WALLAH
Do you want to know which courses/languages you need to do/learn before entering engineering colleges ? (will provide you links to all the best resources available for excelling programming after 500 votes)
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Forward from: LAKSHYA BATCH PHYSICS WALLAH
#CBSE
Central Board of Secondary Education has announced CBSE Board Class 12th Result 2022.
Candidates can check CBSE Term 2 Class 12 result on the official site of CBSE on cbse.gov.in and also on cbseresults.nic.in. The Class 12 result can also be checked on digilocker.gov.in apart from UMANG app.

@physicswallahlakshyavideos


Forward from: LAKSHYA BATCH PHYSICS WALLAH
JEE Main 2022 Updates:
Session 2 admit cards tomorrow, exam from July 25

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Forward from: LAKSHYA BATCH PHYSICS WALLAH
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Forward from: LAKSHYA BATCH PHYSICS WALLAH
Hey Everyone,

@Physicswallahlakshyavideos wishes everyone a Happy Holi 🪅🤴🏻

Stay safe while enjoying all festivities🙌🏻


Forward from: LAKSHYA BATCH PHYSICS WALLAH
CBSE OFFICIAL NOTICE 💪

@Physicswallahlakshyavideos


Forward from: LAKSHYA BATCH PHYSICS WALLAH
Happy Republic day 🇮🇳

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Forward from: LAKSHYA BATCH PHYSICS WALLAH
May millions of diyas illuminate your life with endless joy, prosperity, health and wealth forever. Wishing you and your family a very happy and safe Diwali! 🪔✨

@physicswallahlakshyavideos


Forward from: LAKSHYA BATCH PHYSICS WALLAH
NEET Result Declared.
Check your mail🙃

Those who have not got results via email, do wait.

#NEET
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Forward from: MATHS JEE BITSAT CBSE ICSE Boards NDA
♦️Revision Notes on Arithmetic Progression♦️
If ‘a’ is the first term and ‘d’ is the common difference of the arithmetic progression, then its nth term is given by an = a+(n-1)d

The sum, Sn of the first ‘n’ terms of the A.P. is given by Sn = n/2 [2a + (n-1)d]

If Sn is the sum of n terms of an A.P. whose first term is ‘a’ and last term is ‘l’,Sn = (n/2)(a + l)

If common difference is d, number of terms n and the last term l, then Sn = (n/2)[2l-(n -1)d]

If a fixed number is added or subtracted from each term of an A.P., then the resulting sequence is also an A.P. and it has the same common difference as that of the original A.P.

If each term of A.P is multiplied by some constant or divided by a non-zero fixed constant, the resulting sequence is an A.P. again.

If a1, a2, a3, …, an andb1, b2, b3, …, bn, are in A.P. then a1+b1, a2+b2, a3+b3, ……, an+bn and a1–b1, a2–b2, a3–b3, ……, an–bn will also be in A.P.

Suppose a1, a2, a3, ……,an are in A.P. then an, an–1, ……, a3, a2, a1 will also be in A.P.

If nth term of a series is tn = An + B, then the series is in A.P.

If a1, a2, a3, ……, an are in A.P., then a1 + an = a2 + an–1 = a3 + an–2 = …… and so on.

In order to assume three terms in A.P. whose sum is given, they should be assumed as a-d, a, a+d.

Four terms of the A.P. whose sum is given should be assumed as a-3d, a-d, a+d, a+3d

Five convenient numbers in A.P. a–2b, a–b, a, a+b, a+2 b.

In general, we take a – rd, a – (r – 1)d, …., a – d, a, a + rd in case we have to take (2r + 1) terms in an A.P.

Likewise, any 2r terms of an A.P. should be assumed as: a – (2r-1)d, a – (2r – 3)d, …., a – d, a, a + d, ………….. , a+(2r-3)d, a + (2r-1)d.

The arithmetic mean of two numbers ‘a’ and ‘b’ is (a+b)/2.

The terms A1, A2, ….. , An are said to be arithmetic means between a and b if a, A1, A2, ….. , An, bis an A.P.

Clearly, ‘a’ is the first term, ‘b’ is the (n+2)th term and ‘d’ is the common difference. Then, we have b = a+(n+2-1)d = a+(n+1)d

Hence, this gives ‘d’ = (b-a)/(n+1)

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