For the reaction, N2(g) + 3H2(g) → 2NH3(g) d[NH3]/dt = 2 x10-4 mol L-1s-1, the value of -d[H2]/dt would be
Опрос
- 3 x 10-4 mol L-1s-1
- 4 x 10-4 mol L-1s-1
- 610-4 mol L-1s-1
- 1 x 10-4 mol L-1s-1